Initial commit

14lanqiao/test3-2.cpp

@@ -0,0 +1,26 @@
+#include<bits/stdc++.h>
+using namespace std;
+int main(){
+    int n; cin >> n;
+    int mxv = INT_MIN; int miv = INT_MAX;
+    for(int i = 1; i <= n; i++){
+        int a, b; cin >> a >> b;
+        miv = min(miv, a/b);
+        mxv = max(mxv, a/(b+1)+1);
+    }
+    cout << mxv << " " << miv << endl;
+    return 0;
+}
+/*
+数学优化
+通过floor(A/V) = B，可以推出 A/V =［B,B+1）
+进而得到B <= A/V < B+1，三个表达式同时被A除
+得到关于V的不等式即 A/B >= V > A/(B+1)
+*/
+
+/* test samples
+3
+75 3
+53 2
+59 2
+*/