29 lines
906 B
C++
29 lines
906 B
C++
// lanqiao 3492 日期统计
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#include<bits/stdc++.h>
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using namespace std;
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const int N = 1e2 + 10;
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int a[N] = { 0,5,6,8,6,9,1,6,1,2,4,9,1,9,8,2,3,6,4,7,7,5,9,5,0,3,8,7,5,8,1,5,8,6,1,8,3,0,3,7,9,2,
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7,0,5,8,8,5,7,0,9,9,1,9,4,4,6,8,6,3,3,8,5,1,6,3,4,6,7,0,7,8,2,7,6,8,9,5,6,5,6,1,4,0,1,
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0,0,9,4,8,0,9,1,2,8,5,0,2,5,3,3 }; // 示例数组
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int day[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
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int main(){
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int ans = 0;
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for(int i = 1; i <=12; i++){
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for(int j = 1; j <= day[i]; j++){
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int date[] = {0, 2, 0, 2, 3, i/10, i%10, j/10, j%10 };
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int id = 1;
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for(int i = 1; i<=100; i++){
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if(a[i] == date[id]){
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id++;
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if(id>8){
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ans++;
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break;
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}
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}
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}
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}
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}
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cout << ans << endl;
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return 0;
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} |