14 lines
420 B
C++
14 lines
420 B
C++
// lanqiao 3498 串的熵
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#include<bits/stdc++.h>
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using namespace std;
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int main(){
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double n = 23333333;
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double res = 11625907.5798;
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for(int a = 0; a <= n; a++){ // a为0出现的次数
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int b = n - a; // b为1出现的次数
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if(a>=b) continue;
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double ans = (-1)*a*(a/n)*log2(a/n) + (-1)*b*(b/n)*log2(b/n);
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if(fabs(ans - res) < 1e-4) cout << a << endl;
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}
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return 0;
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} |